Base | Representation |
---|---|
bin | 1010011010001101110110… |
… | …1001000110010101101011 |
3 | 1111112011212100222111001122 |
4 | 2212203131221012111223 |
5 | 3000010401410241042 |
6 | 40201554555205455 |
7 | 2260624304552015 |
oct | 246433551062553 |
9 | 44464770874048 |
10 | 11445511415147 |
11 | 37130178a00a7 |
12 | 134a27274688b |
13 | 6503cb8c4334 |
14 | 2b7d73c911b5 |
15 | 14cacd8617d2 |
hex | a68dda4656b |
11445511415147 has 2 divisors, whose sum is σ = 11445511415148. Its totient is φ = 11445511415146.
The previous prime is 11445511415087. The next prime is 11445511415161. The reversal of 11445511415147 is 74151411554411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11445511415147 - 26 = 11445511415083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11445511415098 and 11445511415107.
It is not a weakly prime, because it can be changed into another prime (11445511415747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5722755707573 + 5722755707574.
It is an arithmetic number, because the mean of its divisors is an integer number (5722755707574).
Almost surely, 211445511415147 is an apocalyptic number.
11445511415147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11445511415147 is an equidigital number, since it uses as much as digits as its factorization.
11445511415147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 224000, while the sum is 44.
Adding to 11445511415147 its reverse (74151411554411), we get a palindrome (85596922969558).
The spelling of 11445511415147 in words is "eleven trillion, four hundred forty-five billion, five hundred eleven million, four hundred fifteen thousand, one hundred forty-seven".
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