Base | Representation |
---|---|
bin | 1010011010011001000111… |
… | …0011011100000110100101 |
3 | 1111112110200000112221202101 |
4 | 2212212101303130012211 |
5 | 3000033044202241423 |
6 | 40203214532212101 |
7 | 2261062226402350 |
oct | 246462163340645 |
9 | 44473600487671 |
10 | 11448534024613 |
11 | 3714328aa3354 |
12 | 134a976a6a031 |
13 | 650790b9394a |
14 | 2b817d4a1297 |
15 | 14cc08dbe7ad |
hex | a6991cdc1a5 |
11448534024613 has 8 divisors (see below), whose sum is σ = 13125313458432. Its totient is φ = 9782073234096.
The previous prime is 11448534024607. The next prime is 11448534024637. The reversal of 11448534024613 is 31642043584411.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11448534024613 - 217 = 11448533893541 is a prime.
It is a super-4 number, since 4×114485340246134 (a number of 53 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11448534024643) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2579658445 + ... + 2579662882.
It is an arithmetic number, because the mean of its divisors is an integer number (1640664182304).
Almost surely, 211448534024613 is an apocalyptic number.
It is an amenable number.
11448534024613 is a deficient number, since it is larger than the sum of its proper divisors (1676779433819).
11448534024613 is an equidigital number, since it uses as much as digits as its factorization.
11448534024613 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5159321651.
The product of its (nonzero) digits is 1105920, while the sum is 46.
The spelling of 11448534024613 in words is "eleven trillion, four hundred forty-eight billion, five hundred thirty-four million, twenty-four thousand, six hundred thirteen".
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