Base | Representation |
---|---|
bin | 10101010100111100… |
… | …10010001111011111 |
3 | 1002112222012021200002 |
4 | 22222132102033133 |
5 | 141422200002401 |
6 | 5132101124515 |
7 | 553512253136 |
oct | 125236221737 |
9 | 32488167602 |
10 | 11450000351 |
11 | 4946254809 |
12 | 22766b973b |
13 | 110622454a |
14 | 7a896c91d |
15 | 47032ca6b |
hex | 2aa7923df |
11450000351 has 2 divisors, whose sum is σ = 11450000352. Its totient is φ = 11450000350.
The previous prime is 11450000347. The next prime is 11450000357. The reversal of 11450000351 is 15300005411.
It is a weak prime.
It is an emirp because it is prime and its reverse (15300005411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11450000351 - 22 = 11450000347 is a prime.
It is a super-2 number, since 2×114500003512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11450000357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5725000175 + 5725000176.
It is an arithmetic number, because the mean of its divisors is an integer number (5725000176).
Almost surely, 211450000351 is an apocalyptic number.
11450000351 is a deficient number, since it is larger than the sum of its proper divisors (1).
11450000351 is an equidigital number, since it uses as much as digits as its factorization.
11450000351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 20.
Adding to 11450000351 its reverse (15300005411), we get a palindrome (26750005762).
The spelling of 11450000351 in words is "eleven billion, four hundred fifty million, three hundred fifty-one", and thus it is an aban number.
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