114500413151 has 2 divisors, whose sum is σ = 114500413152. Its totient is φ = 114500413150.

The previous prime is 114500413147. The next prime is 114500413169. The reversal of 114500413151 is 151314005411.

It is a weak prime.

It is an emirp because it is prime and its reverse (151314005411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114500413151 - 2² = 114500413147 is a prime.

It is a super-2 number, since 2×114500413151² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 114500413151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114500415151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57250206575 + 57250206576.

It is an arithmetic number, because the mean of its divisors is an integer number (57250206576).

Almost surely, 2^114500413151 is an apocalyptic number.

114500413151 is a deficient number, since it is larger than the sum of its proper divisors (1).

114500413151 is an equidigital number, since it uses as much as digits as its factorization.

114500413151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1200, while the sum is 26.

Adding to 114500413151 its reverse (151314005411), we get a palindrome (265814418562).

The spelling of 114500413151 in words is "one hundred fourteen billion, five hundred million, four hundred thirteen thousand, one hundred fifty-one".