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114505325099993 is a prime number
BaseRepresentation
bin11010000010010001011001…
…001110100011101111011001
3120000102121020222120022012102
4122002101121032203233121
5110002023401211144433
61043311004204253145
733055510462146242
oct3202213116435731
9500377228508172
10114505325099993
1133537487964743
1210a13a958411b5
134bb7a62521ba9
14203c1317cdcc9
15d3882da734e8
hex6824593a3bd9

114505325099993 has 2 divisors, whose sum is σ = 114505325099994. Its totient is φ = 114505325099992.

The previous prime is 114505325099969. The next prime is 114505325100097. The reversal of 114505325099993 is 399990523505411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93955858044889 + 20549467055104 = 9693083^2 + 4533152^2 .

It is a cyclic number.

It is not a de Polignac number, because 114505325099993 - 226 = 114505257991129 is a prime.

It is a super-2 number, since 2×1145053250999932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114505325099933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57252662549996 + 57252662549997.

It is an arithmetic number, because the mean of its divisors is an integer number (57252662549997).

Almost surely, 2114505325099993 is an apocalyptic number.

It is an amenable number.

114505325099993 is a deficient number, since it is larger than the sum of its proper divisors (1).

114505325099993 is an equidigital number, since it uses as much as digits as its factorization.

114505325099993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 59049000, while the sum is 65.

The spelling of 114505325099993 in words is "one hundred fourteen trillion, five hundred five billion, three hundred twenty-five million, ninety-nine thousand, nine hundred ninety-three".