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11451010153 = 111951533573
BaseRepresentation
bin10101010101000100…
…01000110001101001
31002120001002120212011
422222202020301221
5141422424311103
65132134515521
7553523660152
oct125242106151
932501076764
1011451010153
114946884460
122276b05ba1
1311064b906b
147a8b52929
1547047bd6d
hex2aa888c69

11451010153 has 8 divisors (see below), whose sum is σ = 12498437376. Its totient is φ = 10404654000.

The previous prime is 11451010073. The next prime is 11451010189. The reversal of 11451010153 is 35101015411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11451010153 - 233 = 2861075561 is a prime.

It is a super-2 number, since 2×114510101532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11451080153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 245326 + ... + 288247.

It is an arithmetic number, because the mean of its divisors is an integer number (1562304672).

Almost surely, 211451010153 is an apocalyptic number.

It is an amenable number.

11451010153 is a deficient number, since it is larger than the sum of its proper divisors (1047427223).

11451010153 is a wasteful number, since it uses less digits than its factorization.

11451010153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 535535.

The product of its (nonzero) digits is 300, while the sum is 22.

Adding to 11451010153 its reverse (35101015411), we get a palindrome (46552025564).

The spelling of 11451010153 in words is "eleven billion, four hundred fifty-one million, ten thousand, one hundred fifty-three".

Divisors: 1 11 1951 21461 533573 5869303 1041000923 11451010153