Base | Representation |
---|---|
bin | 11010000010010110111000… |
… | …000111011001000101010111 |
3 | 120000110011110020212000222111 |
4 | 122002112320013121011113 |
5 | 110002122430234233101 |
6 | 1043313420301411451 |
7 | 33056106404162365 |
oct | 3202267007310527 |
9 | 500404406760874 |
10 | 114511212024151 |
11 | 33539a28982a18 |
12 | 10a15059269b87 |
13 | 4bb8490049577 |
14 | 203c52d5a6635 |
15 | d38a757c2251 |
hex | 6825b81d9157 |
114511212024151 has 2 divisors, whose sum is σ = 114511212024152. Its totient is φ = 114511212024150.
The previous prime is 114511212024029. The next prime is 114511212024179. The reversal of 114511212024151 is 151420212115411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114511212024151 - 225 = 114511178469719 is a prime.
It is a super-2 number, since 2×1145112120241512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114511212324151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255606012075 + 57255606012076.
It is an arithmetic number, because the mean of its divisors is an integer number (57255606012076).
Almost surely, 2114511212024151 is an apocalyptic number.
114511212024151 is a deficient number, since it is larger than the sum of its proper divisors (1).
114511212024151 is an equidigital number, since it uses as much as digits as its factorization.
114511212024151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3200, while the sum is 31.
Adding to 114511212024151 its reverse (151420212115411), we get a palindrome (265931424139562).
The spelling of 114511212024151 in words is "one hundred fourteen trillion, five hundred eleven billion, two hundred twelve million, twenty-four thousand, one hundred fifty-one".
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