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114511320042151 is a prime number
BaseRepresentation
bin11010000010010110111110…
…100011011100101010100111
3120000110011201210002220211011
4122002112332203130222213
5110002123140412322101
61043313435120523051
733056112155260564
oct3202267643345247
9500404653086734
10114511320042151
1133539a8395049a
1210a15089480487
134bb84a9539746
14203c53da8386b
15d38a8000c751
hex6825be8dcaa7

114511320042151 has 2 divisors, whose sum is σ = 114511320042152. Its totient is φ = 114511320042150.

The previous prime is 114511320042127. The next prime is 114511320042181. The reversal of 114511320042151 is 151240023115411.

It is a weak prime.

It is an emirp because it is prime and its reverse (151240023115411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114511320042151 - 231 = 114509172558503 is a prime.

It is a super-2 number, since 2×1145113200421512 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114511320042181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255660021075 + 57255660021076.

It is an arithmetic number, because the mean of its divisors is an integer number (57255660021076).

Almost surely, 2114511320042151 is an apocalyptic number.

114511320042151 is a deficient number, since it is larger than the sum of its proper divisors (1).

114511320042151 is an equidigital number, since it uses as much as digits as its factorization.

114511320042151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 31.

Adding to 114511320042151 its reverse (151240023115411), we get a palindrome (265751343157562).

The spelling of 114511320042151 in words is "one hundred fourteen trillion, five hundred eleven billion, three hundred twenty million, forty-two thousand, one hundred fifty-one".