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114512314014335 = 5241156836059489
BaseRepresentation
bin11010000010010111111001…
…110011001001101001111111
3120000110021022001102221022202
4122002113321303021221333
5110002132204341424320
61043314121505102115
733056145615014636
oct3202277163115177
9500407261387282
10114512314014335
113353a443a27506
1210a1530632793b
134bb8607446073
14203c5d5aa251d
15d38adc3ecb75
hex6825f9cc9a7f

114512314014335 has 16 divisors (see below), whose sum is σ = 137993783764320. Its totient is φ = 91223895183360.

The previous prime is 114512314014317. The next prime is 114512314014383. The reversal of 114512314014335 is 533410413215411.

It is not a de Polignac number, because 114512314014335 - 212 = 114512314010239 is a prime.

It is a super-3 number, since 3×1145123140143353 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15868271 + ... + 21927759.

It is an arithmetic number, because the mean of its divisors is an integer number (8624611485270).

Almost surely, 2114512314014335 is an apocalyptic number.

114512314014335 is a deficient number, since it is larger than the sum of its proper divisors (23481469749985).

114512314014335 is a wasteful number, since it uses less digits than its factorization.

114512314014335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6075418.

The product of its (nonzero) digits is 86400, while the sum is 38.

Adding to 114512314014335 its reverse (533410413215411), we get a palindrome (647922727229746).

The spelling of 114512314014335 in words is "one hundred fourteen trillion, five hundred twelve billion, three hundred fourteen million, fourteen thousand, three hundred thirty-five".

Divisors: 1 5 241 1205 15683 78415 3779603 6059489 18898015 30297445 1460336849 7301684245 95030965987 475154829935 22902462802867 114512314014335