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11451353497 is a prime number
BaseRepresentation
bin10101010101000110…
…11100100110011001
31002120001202000211121
422222203130212121
5141423021302442
65132150125241
7553526620153
oct125243344631
932501660747
1011451353497
114946a99411
122277050821
1311065a941c
147a8c01ad3
154704e8967
hex2aa8dc999

11451353497 has 2 divisors, whose sum is σ = 11451353498. Its totient is φ = 11451353496.

The previous prime is 11451353489. The next prime is 11451353533. The reversal of 11451353497 is 79435315411.

11451353497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7130789136 + 4320564361 = 84444^2 + 65731^2 .

It is a cyclic number.

It is not a de Polignac number, because 11451353497 - 23 = 11451353489 is a prime.

It is a super-2 number, since 2×114513534972 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11451353897) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5725676748 + 5725676749.

It is an arithmetic number, because the mean of its divisors is an integer number (5725676749).

Almost surely, 211451353497 is an apocalyptic number.

It is an amenable number.

11451353497 is a deficient number, since it is larger than the sum of its proper divisors (1).

11451353497 is an equidigital number, since it uses as much as digits as its factorization.

11451353497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 226800, while the sum is 43.

The spelling of 11451353497 in words is "eleven billion, four hundred fifty-one million, three hundred fifty-three thousand, four hundred ninety-seven".