Base | Representation |
---|---|
bin | 10101010101001100… |
… | …00101000001010011 |
3 | 1002120010001002010121 |
4 | 22222212011001103 |
5 | 141423210341342 |
6 | 5132213011111 |
7 | 553535522323 |
oct | 125246050123 |
9 | 32503032117 |
10 | 11452043347 |
11 | 494741a738 |
12 | 2277323a97 |
13 | 110678b414 |
14 | 7a8d41283 |
15 | 4705d3067 |
hex | 2aa985053 |
11452043347 has 2 divisors, whose sum is σ = 11452043348. Its totient is φ = 11452043346.
The previous prime is 11452043293. The next prime is 11452043381. The reversal of 11452043347 is 74334025411.
It is an a-pointer prime, because the next prime (11452043381) can be obtained adding 11452043347 to its sum of digits (34).
It is a strong prime.
It is an emirp because it is prime and its reverse (74334025411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11452043347 - 211 = 11452041299 is a prime.
It is a super-2 number, since 2×114520433472 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11452043947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5726021673 + 5726021674.
It is an arithmetic number, because the mean of its divisors is an integer number (5726021674).
Almost surely, 211452043347 is an apocalyptic number.
11452043347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11452043347 is an equidigital number, since it uses as much as digits as its factorization.
11452043347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 11452043347 its reverse (74334025411), we get a palindrome (85786068758).
The spelling of 11452043347 in words is "eleven billion, four hundred fifty-two million, forty-three thousand, three hundred forty-seven".
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