Base | Representation |
---|---|
bin | 11010000010100010000011… |
… | …111010110101101100011111 |
3 | 120000111022110012021101211122 |
4 | 122002202003322311230133 |
5 | 110002322024113021002 |
6 | 1043323124100241155 |
7 | 33060013116516506 |
oct | 3202420372655437 |
9 | 500438405241748 |
10 | 114523221220127 |
11 | 33544030845675 |
12 | 10a1744b0a01bb |
13 | 4bb96550809a5 |
14 | 203cd4c4d983d |
15 | d39029c5c6a2 |
hex | 682883eb5b1f |
114523221220127 has 2 divisors, whose sum is σ = 114523221220128. Its totient is φ = 114523221220126.
The previous prime is 114523221220081. The next prime is 114523221220157. The reversal of 114523221220127 is 721022122325411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 114523221220127 - 242 = 110125174709023 is a prime.
It is a super-2 number, since 2×1145232212201272 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114523221220157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57261610610063 + 57261610610064.
It is an arithmetic number, because the mean of its divisors is an integer number (57261610610064).
Almost surely, 2114523221220127 is an apocalyptic number.
114523221220127 is a deficient number, since it is larger than the sum of its proper divisors (1).
114523221220127 is an equidigital number, since it uses as much as digits as its factorization.
114523221220127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26880, while the sum is 35.
Adding to 114523221220127 its reverse (721022122325411), we get a palindrome (835545343545538).
The spelling of 114523221220127 in words is "one hundred fourteen trillion, five hundred twenty-three billion, two hundred twenty-one million, two hundred twenty thousand, one hundred twenty-seven".
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