Base | Representation |
---|---|
bin | 1010011010101100000110… |
… | …0101001011110000011111 |
3 | 1111112221211012120211202211 |
4 | 2212223001211023300133 |
5 | 3000124013410430221 |
6 | 40205420352501251 |
7 | 2261332433266051 |
oct | 246530145136037 |
9 | 44487735524684 |
10 | 11453630561311 |
11 | 3716503946854 |
12 | 134b95984a827 |
13 | 6510c3a22833 |
14 | 2b85042d18d1 |
15 | 14ce065446e1 |
hex | a6ac194bc1f |
11453630561311 has 4 divisors (see below), whose sum is σ = 11454458089824. Its totient is φ = 11452803032800.
The previous prime is 11453630561287. The next prime is 11453630561353. The reversal of 11453630561311 is 11316503635411.
11453630561311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11453630561311 - 27 = 11453630561183 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11453630561381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 413743495 + ... + 413771176.
It is an arithmetic number, because the mean of its divisors is an integer number (2863614522456).
Almost surely, 211453630561311 is an apocalyptic number.
11453630561311 is a deficient number, since it is larger than the sum of its proper divisors (827528513).
11453630561311 is an equidigital number, since it uses as much as digits as its factorization.
11453630561311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 827528512.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 11453630561311 in words is "eleven trillion, four hundred fifty-three billion, six hundred thirty million, five hundred sixty-one thousand, three hundred eleven".
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