Base | Representation |
---|---|
bin | 11010000010110011101001… |
… | …111110001001000110111011 |
3 | 120000120010012210221000010211 |
4 | 122002303221332021012323 |
5 | 110003124221441400131 |
6 | 1043335530445451551 |
7 | 33061252226125324 |
oct | 3202635176110673 |
9 | 500503183830124 |
10 | 114542113231291 |
11 | 335510458a3239 |
12 | 10a1b041b70bb7 |
13 | 4bbb37603b615 |
14 | 203dc215a344b |
15 | d397835b55b1 |
hex | 682ce9f891bb |
114542113231291 has 2 divisors, whose sum is σ = 114542113231292. Its totient is φ = 114542113231290.
The previous prime is 114542113231207. The next prime is 114542113231307. The reversal of 114542113231291 is 192132311245411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114542113231291 is a prime.
It is not a weakly prime, because it can be changed into another prime (114542113631291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271056615645 + 57271056615646.
It is an arithmetic number, because the mean of its divisors is an integer number (57271056615646).
Almost surely, 2114542113231291 is an apocalyptic number.
114542113231291 is a deficient number, since it is larger than the sum of its proper divisors (1).
114542113231291 is an equidigital number, since it uses as much as digits as its factorization.
114542113231291 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 51840, while the sum is 40.
The spelling of 114542113231291 in words is "one hundred fourteen trillion, five hundred forty-two billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred ninety-one".
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