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114542113231207 is a prime number
BaseRepresentation
bin11010000010110011101001…
…111110001001000101100111
3120000120010012210221000000201
4122002303221332021011213
5110003124221441344312
61043335530445451331
733061252226125144
oct3202635176110547
9500503183830021
10114542113231207
11335510458a3172
1210a1b041b70b47
134bbb37603b57c
14203dc215a33cb
15d397835b5557
hex682ce9f89167

114542113231207 has 2 divisors, whose sum is σ = 114542113231208. Its totient is φ = 114542113231206.

The previous prime is 114542113231193. The next prime is 114542113231291. The reversal of 114542113231207 is 702132311245411.

It is a weak prime.

It is an emirp because it is prime and its reverse (702132311245411) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114542113231207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114542113231307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271056615603 + 57271056615604.

It is an arithmetic number, because the mean of its divisors is an integer number (57271056615604).

Almost surely, 2114542113231207 is an apocalyptic number.

114542113231207 is a deficient number, since it is larger than the sum of its proper divisors (1).

114542113231207 is an equidigital number, since it uses as much as digits as its factorization.

114542113231207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 37.

Adding to 114542113231207 its reverse (702132311245411), we get a palindrome (816674424476618).

The spelling of 114542113231207 in words is "one hundred fourteen trillion, five hundred forty-two billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred seven".