Base | Representation |
---|---|
bin | 10000101010110001100… |
… | …111100100100000111111 |
3 | 11001111120202202222212021 |
4 | 100222301213210200333 |
5 | 122231330424204101 |
6 | 2234113005021011 |
7 | 145520046622114 |
oct | 20526147444077 |
9 | 4044522688767 |
10 | 1145441241151 |
11 | 4018627a0049 |
12 | 165bb1b54767 |
13 | 8402623a44c |
14 | 3d62259490b |
15 | 1ebdeeec5a1 |
hex | 10ab19e483f |
1145441241151 has 4 divisors (see below), whose sum is σ = 1151438315904. Its totient is φ = 1139444166400.
The previous prime is 1145441241121. The next prime is 1145441241173. The reversal of 1145441241151 is 1511421445411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1145441241151 - 213 = 1145441232959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1145441241101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2998537090 + ... + 2998537471.
It is an arithmetic number, because the mean of its divisors is an integer number (287859578976).
Almost surely, 21145441241151 is an apocalyptic number.
1145441241151 is a deficient number, since it is larger than the sum of its proper divisors (5997074753).
1145441241151 is an equidigital number, since it uses as much as digits as its factorization.
1145441241151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5997074752.
The product of its digits is 12800, while the sum is 34.
Adding to 1145441241151 its reverse (1511421445411), we get a palindrome (2656862686562).
The spelling of 1145441241151 in words is "one trillion, one hundred forty-five billion, four hundred forty-one million, two hundred forty-one thousand, one hundred fifty-one".
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