Base | Representation |
---|---|
bin | 1010011010110001101101… |
… | …0000101010001000100111 |
3 | 1111120002201001200212012200 |
4 | 2212230123100222020213 |
5 | 3000140104043131101 |
6 | 40210225540545543 |
7 | 2261414633023116 |
oct | 246543320521047 |
9 | 44502631625180 |
10 | 11455135130151 |
11 | 3717106167679 |
12 | 13500b96b22b3 |
13 | 6512a365455b |
14 | 2b8608063c7d |
15 | 14ce93692986 |
hex | a6b1b42a227 |
11455135130151 has 6 divisors (see below), whose sum is σ = 16546306299120. Its totient is φ = 7636756753428.
The previous prime is 11455135130123. The next prime is 11455135130167. The reversal of 11455135130151 is 15103153155411.
11455135130151 is a `hidden beast` number, since 1 + 1 + 4 + 5 + 513 + 5 + 130 + 1 + 5 + 1 = 666.
It is not a de Polignac number, because 11455135130151 - 215 = 11455135097383 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11455135130051) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 636396396111 + ... + 636396396128.
It is an arithmetic number, because the mean of its divisors is an integer number (2757717716520).
Almost surely, 211455135130151 is an apocalyptic number.
11455135130151 is a deficient number, since it is larger than the sum of its proper divisors (5091171168969).
11455135130151 is a wasteful number, since it uses less digits than its factorization.
11455135130151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1272792792245 (or 1272792792242 counting only the distinct ones).
The product of its (nonzero) digits is 22500, while the sum is 36.
Adding to 11455135130151 its reverse (15103153155411), we get a palindrome (26558288285562).
The spelling of 11455135130151 in words is "eleven trillion, four hundred fifty-five billion, one hundred thirty-five million, one hundred thirty thousand, one hundred fifty-one".
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