Base | Representation |
---|---|
bin | 10000101010110101111… |
… | …101100011100110111111 |
3 | 11001111202211220021220002 |
4 | 100222311331203212333 |
5 | 122232003103112341 |
6 | 2234124130544515 |
7 | 145521623210630 |
oct | 20526575434677 |
9 | 4044684807802 |
10 | 1145514113471 |
11 | 40189a943102 |
12 | 16601243813b |
13 | 84038373470 |
14 | 3d62c123887 |
15 | 1ebe65e429b |
hex | 10ab5f639bf |
1145514113471 has 32 divisors (see below), whose sum is σ = 1417975910400. Its totient is φ = 901132366464.
The previous prime is 1145514113453. The next prime is 1145514113479. The reversal of 1145514113471 is 1743114155411.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1145514113471 is a prime.
It is a super-3 number, since 3×11455141134713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1145514113479) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25746881 + ... + 25791333.
It is an arithmetic number, because the mean of its divisors is an integer number (44311747200).
Almost surely, 21145514113471 is an apocalyptic number.
1145514113471 is a deficient number, since it is larger than the sum of its proper divisors (272461796929).
1145514113471 is a wasteful number, since it uses less digits than its factorization.
1145514113471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46095.
The product of its digits is 33600, while the sum is 38.
Adding to 1145514113471 its reverse (1743114155411), we get a palindrome (2888628268882).
The spelling of 1145514113471 in words is "one trillion, one hundred forty-five billion, five hundred fourteen million, one hundred thirteen thousand, four hundred seventy-one".
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