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11455142131247 is a prime number
BaseRepresentation
bin1010011010110001101110…
…1011010111011000101111
31111120002201112212112220112
42212230123223113120233
53000140112341144442
640210230351010235
72261415046362353
oct246543353273057
944502645775815
1011455142131247
11371710a109701
1213500bbb0997b
136512a4c36109
142b8608d67463
1514ce940c7082
hexa6b1bad762f

11455142131247 has 2 divisors, whose sum is σ = 11455142131248. Its totient is φ = 11455142131246.

The previous prime is 11455142131163. The next prime is 11455142131327. The reversal of 11455142131247 is 74213124155411.

It is a strong prime.

It is an emirp because it is prime and its reverse (74213124155411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11455142131247 - 216 = 11455142065711 is a prime.

It is a super-2 number, since 2×114551421312472 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11455142137247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5727571065623 + 5727571065624.

It is an arithmetic number, because the mean of its divisors is an integer number (5727571065624).

Almost surely, 211455142131247 is an apocalyptic number.

11455142131247 is a deficient number, since it is larger than the sum of its proper divisors (1).

11455142131247 is an equidigital number, since it uses as much as digits as its factorization.

11455142131247 is an evil number, because the sum of its binary digits is even.

The product of its digits is 134400, while the sum is 41.

Adding to 11455142131247 its reverse (74213124155411), we get a palindrome (85668266286658).

The spelling of 11455142131247 in words is "eleven trillion, four hundred fifty-five billion, one hundred forty-two million, one hundred thirty-one thousand, two hundred forty-seven".