Base | Representation |
---|---|
bin | 1010011010110110110010… |
… | …1001100100001110000111 |
3 | 1111120020020020002121221102 |
4 | 2212231230221210032013 |
5 | 3000200403124122043 |
6 | 40211013240010315 |
7 | 2261463523320503 |
oct | 246555451441607 |
9 | 44506206077842 |
10 | 11456500614023 |
11 | 3717746a20943 |
12 | 135041aa6099b |
13 | 65146050958a |
14 | 2b86d754d303 |
15 | 14d0234ba6b8 |
hex | a6b6ca64387 |
11456500614023 has 2 divisors, whose sum is σ = 11456500614024. Its totient is φ = 11456500614022.
The previous prime is 11456500613993. The next prime is 11456500614067. The reversal of 11456500614023 is 32041600565411.
11456500614023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (32041600565411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11456500614023 - 214 = 11456500597639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11456500613023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5728250307011 + 5728250307012.
It is an arithmetic number, because the mean of its divisors is an integer number (5728250307012).
Almost surely, 211456500614023 is an apocalyptic number.
11456500614023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11456500614023 is an equidigital number, since it uses as much as digits as its factorization.
11456500614023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
The spelling of 11456500614023 in words is "eleven trillion, four hundred fifty-six billion, five hundred million, six hundred fourteen thousand, twenty-three".
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