Base | Representation |
---|---|
bin | 10101011001110000… |
… | …00011100100011011 |
3 | 1002122210001020200212 |
4 | 22230320003210123 |
5 | 142013004413202 |
6 | 5140101121335 |
7 | 554512012211 |
oct | 125470034433 |
9 | 32583036625 |
10 | 11490310427 |
11 | 4966a87322 |
12 | 22880b924b |
13 | 111169926b |
14 | 7b0062cb1 |
15 | 473b41652 |
hex | 2ace0391b |
11490310427 has 2 divisors, whose sum is σ = 11490310428. Its totient is φ = 11490310426.
The previous prime is 11490310369. The next prime is 11490310459. The reversal of 11490310427 is 72401309411.
It is an a-pointer prime, because the next prime (11490310459) can be obtained adding 11490310427 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11490310427 - 28 = 11490310171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11490310393 and 11490310402.
It is not a weakly prime, because it can be changed into another prime (11490315427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5745155213 + 5745155214.
It is an arithmetic number, because the mean of its divisors is an integer number (5745155214).
Almost surely, 211490310427 is an apocalyptic number.
11490310427 is a deficient number, since it is larger than the sum of its proper divisors (1).
11490310427 is an equidigital number, since it uses as much as digits as its factorization.
11490310427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 11490310427 its reverse (72401309411), we get a palindrome (83891619838).
The spelling of 11490310427 in words is "eleven billion, four hundred ninety million, three hundred ten thousand, four hundred twenty-seven".
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