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1149380254447 is a prime number
BaseRepresentation
bin10000101110011100011…
…001101101101011101111
311001212202021201121021121
4100232130121231223233
5122312412321120242
62240003515441411
7146016466651645
oct20563431555357
94055667647247
101149380254447
114034a420a037
12166911156267
1384503327a49
143d8b7791195
151ed70c27667
hex10b9c66daef

1149380254447 has 2 divisors, whose sum is σ = 1149380254448. Its totient is φ = 1149380254446.

The previous prime is 1149380254357. The next prime is 1149380254453. The reversal of 1149380254447 is 7444520839411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1149380254447 - 223 = 1149371865839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1149380254394 and 1149380254403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1149380254487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574690127223 + 574690127224.

It is an arithmetic number, because the mean of its divisors is an integer number (574690127224).

Almost surely, 21149380254447 is an apocalyptic number.

1149380254447 is a deficient number, since it is larger than the sum of its proper divisors (1).

1149380254447 is an equidigital number, since it uses as much as digits as its factorization.

1149380254447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3870720, while the sum is 52.

The spelling of 1149380254447 in words is "one trillion, one hundred forty-nine billion, three hundred eighty million, two hundred fifty-four thousand, four hundred forty-seven".