11496133441 has 4 divisors (see below), whose sum is σ = 12380451412. Its totient is φ = 10611815472.

The previous prime is 11496133417. The next prime is 11496133457. The reversal of 11496133441 is 14433169411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1706020416 + 9790113025 = 41304^2 + 98945^2 .

It is a cyclic number.

It is not a de Polignac number, because 11496133441 - 2²¹ = 11494036289 is a prime.

It is a super-2 number, since 2×11496133441² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11496133441.

It is not an unprimeable number, because it can be changed into a prime (11496130441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 442158966 + ... + 442158991.

It is an arithmetic number, because the mean of its divisors is an integer number (3095112853).

Almost surely, 2^11496133441 is an apocalyptic number.

It is an amenable number.

11496133441 is a deficient number, since it is larger than the sum of its proper divisors (884317971).

11496133441 is an equidigital number, since it uses as much as digits as its factorization.

11496133441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 884317970.

The product of its digits is 31104, while the sum is 37.

The spelling of 11496133441 in words is "eleven billion, four hundred ninety-six million, one hundred thirty-three thousand, four hundred forty-one".