1149693410053 has 2 divisors, whose sum is σ = 1149693410054. Its totient is φ = 1149693410052.

The previous prime is 1149693410039. The next prime is 1149693410081. The reversal of 1149693410053 is 3500143969411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 803063315044 + 346630095009 = 896138^2 + 588753^2 .

It is a cyclic number.

It is not a de Polignac number, because 1149693410053 - 2²⁵ = 1149659855621 is a prime.

It is a super-3 number, since 3×1149693410053³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1149693409985 and 1149693410012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1149693410653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574846705026 + 574846705027.

It is an arithmetic number, because the mean of its divisors is an integer number (574846705027).

Almost surely, 2^{1149693410053} is an apocalyptic number.

It is an amenable number.

1149693410053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1149693410053 is an equidigital number, since it uses as much as digits as its factorization.

1149693410053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 349920, while the sum is 46.

The spelling of 1149693410053 in words is "one trillion, one hundred forty-nine billion, six hundred ninety-three million, four hundred ten thousand, fifty-three".