Base | Representation |
---|---|
bin | 10000101110110110011… |
… | …011001101110111011111 |
3 | 11001220212201021021001122 |
4 | 100232312123031313133 |
5 | 122314311103343111 |
6 | 2240115113401155 |
7 | 146033351005604 |
oct | 20566633156737 |
9 | 4056781237048 |
10 | 1149816856031 |
11 | 4036a8704298 |
12 | 166a134091bb |
13 | 8457291308c |
14 | 3d9197626ab |
15 | 1ed9921acdb |
hex | 10bb66cdddf |
1149816856031 has 2 divisors, whose sum is σ = 1149816856032. Its totient is φ = 1149816856030.
The previous prime is 1149816855997. The next prime is 1149816856061. The reversal of 1149816856031 is 1306586189411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1149816856031 - 222 = 1149812661727 is a prime.
It is a super-3 number, since 3×11498168560313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1149816856061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574908428015 + 574908428016.
It is an arithmetic number, because the mean of its divisors is an integer number (574908428016).
Almost surely, 21149816856031 is an apocalyptic number.
1149816856031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1149816856031 is an equidigital number, since it uses as much as digits as its factorization.
1149816856031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 53.
The spelling of 1149816856031 in words is "one trillion, one hundred forty-nine billion, eight hundred sixteen million, eight hundred fifty-six thousand, thirty-one".
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