Base | Representation |
---|---|
bin | 10101011010111101… |
… | …00110010111100001 |
3 | 1002200111001120210022 |
4 | 22231132212113201 |
5 | 142023101230213 |
6 | 5141101443225 |
7 | 554663624024 |
oct | 125536462741 |
9 | 32614046708 |
10 | 11500414433 |
11 | 4971758642 |
12 | 228b570515 |
13 | 11137c6271 |
14 | 7b15331bb |
15 | 47498a308 |
hex | 2ad7a65e1 |
11500414433 has 8 divisors (see below), whose sum is σ = 11793939360. Its totient is φ = 11207509920.
The previous prime is 11500414423. The next prime is 11500414511. The reversal of 11500414433 is 33441400511.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11500414433 - 24 = 11500414417 is a prime.
It is a super-2 number, since 2×115004144332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11500414423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117443 + ... + 191816.
It is an arithmetic number, because the mean of its divisors is an integer number (1474242420).
Almost surely, 211500414433 is an apocalyptic number.
It is an amenable number.
11500414433 is a deficient number, since it is larger than the sum of its proper divisors (293524927).
11500414433 is an equidigital number, since it uses as much as digits as its factorization.
11500414433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 310207.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 11500414433 its reverse (33441400511), we get a palindrome (44941814944).
The spelling of 11500414433 in words is "eleven billion, five hundred million, four hundred fourteen thousand, four hundred thirty-three".
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