115011111322431 has 24 divisors (see below), whose sum is σ = 166377167130720. Its totient is φ = 76558740627456.

The previous prime is 115011111322423. The next prime is 115011111322439. The reversal of 115011111322431 is 134223111110511.

115011111322431 is a `hidden beast` number, since 1 + 1 + 5 + 0 + 111 + 113 + 2 + 2 + 431 = 666.

It is an interprime number because it is at equal distance from previous prime (115011111322423) and next prime (115011111322439).

It is not a de Polignac number, because 115011111322431 - 2³ = 115011111322423 is a prime.

It is a super-2 number, since 2×115011111322431² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 115011111322395 and 115011111322404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115011111322439) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23360215 + ... + 27851783.

It is an arithmetic number, because the mean of its divisors is an integer number (6932381963780).

Almost surely, 2^{115011111322431} is an apocalyptic number.

115011111322431 is a deficient number, since it is larger than the sum of its proper divisors (51366055808289).

115011111322431 is a wasteful number, since it uses less digits than its factorization.

115011111322431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4495855 (or 4495852 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 27.

Adding to 115011111322431 its reverse (134223111110511), we get a palindrome (249234222432942).

The spelling of 115011111322431 in words is "one hundred fifteen trillion, eleven billion, one hundred eleven million, three hundred twenty-two thousand, four hundred thirty-one".