115021234408253 has 2 divisors, whose sum is σ = 115021234408254. Its totient is φ = 115021234408252.

The previous prime is 115021234408207. The next prime is 115021234408261. The reversal of 115021234408253 is 352804432120511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83921227687609 + 31100006720644 = 9160853^2 + 5576738^2 .

It is a cyclic number.

It is not a de Polignac number, because 115021234408253 - 2¹⁶ = 115021234342717 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115021234408253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115021234608253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57510617204126 + 57510617204127.

It is an arithmetic number, because the mean of its divisors is an integer number (57510617204127).

Almost surely, 2^{115021234408253} is an apocalyptic number.

It is an amenable number.

115021234408253 is a deficient number, since it is larger than the sum of its proper divisors (1).

115021234408253 is an equidigital number, since it uses as much as digits as its factorization.

115021234408253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 41.

Adding to 115021234408253 its reverse (352804432120511), we get a palindrome (467825666528764).

The spelling of 115021234408253 in words is "one hundred fifteen trillion, twenty-one billion, two hundred thirty-four million, four hundred eight thousand, two hundred fifty-three".