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115025205013 is a prime number
BaseRepresentation
bin110101100100000001…
…0010101011100010101
3101222220022012211201021
41223020002111130111
53341032423030023
6124501501201141
711211301052635
oct1531002253425
9358808184637
10115025205013
1144866803004
121a3618601b1
13ab016420b4
1457d27666c5
152ed337c35d
hex1ac8095715

115025205013 has 2 divisors, whose sum is σ = 115025205014. Its totient is φ = 115025205012.

The previous prime is 115025204897. The next prime is 115025205023. The reversal of 115025205013 is 310502520511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102404480049 + 12620724964 = 320007^2 + 112342^2 .

It is a cyclic number.

It is not a de Polignac number, because 115025205013 - 217 = 115025073941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115025205023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57512602506 + 57512602507.

It is an arithmetic number, because the mean of its divisors is an integer number (57512602507).

Almost surely, 2115025205013 is an apocalyptic number.

It is an amenable number.

115025205013 is a deficient number, since it is larger than the sum of its proper divisors (1).

115025205013 is an equidigital number, since it uses as much as digits as its factorization.

115025205013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1500, while the sum is 25.

Adding to 115025205013 its reverse (310502520511), we get a palindrome (425527725524).

The spelling of 115025205013 in words is "one hundred fifteen billion, twenty-five million, two hundred five thousand, thirteen".