11503115137 has 2 divisors, whose sum is σ = 11503115138. Its totient is φ = 11503115136.

The previous prime is 11503115101. The next prime is 11503115153. The reversal of 11503115137 is 73151130511.

11503115137 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6684534081 + 4818581056 = 81759^2 + 69416^2 .

It is an emirp because it is prime and its reverse (73151130511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11503115137 - 2¹⁵ = 11503082369 is a prime.

It is a super-3 number, since 3×11503115137³ (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11503115237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5751557568 + 5751557569.

It is an arithmetic number, because the mean of its divisors is an integer number (5751557569).

Almost surely, 2^11503115137 is an apocalyptic number.

It is an amenable number.

11503115137 is a deficient number, since it is larger than the sum of its proper divisors (1).

11503115137 is an equidigital number, since it uses as much as digits as its factorization.

11503115137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1575, while the sum is 28.

Adding to 11503115137 its reverse (73151130511), we get a palindrome (84654245648).

The spelling of 11503115137 in words is "eleven billion, five hundred three million, one hundred fifteen thousand, one hundred thirty-seven".