Base | Representation |
---|---|
bin | 10101011011010010… |
… | …11010001100001111 |
3 | 1002200200101112220112 |
4 | 22231221122030033 |
5 | 142024312420033 |
6 | 5141242310235 |
7 | 555026665412 |
oct | 125551321417 |
9 | 32620345815 |
10 | 11503248143 |
11 | 4973313652 |
12 | 22904b837b |
13 | 111427900a |
14 | 7b1a6db79 |
15 | 474d49c48 |
hex | 2ada5a30f |
11503248143 has 2 divisors, whose sum is σ = 11503248144. Its totient is φ = 11503248142.
The previous prime is 11503248079. The next prime is 11503248161. The reversal of 11503248143 is 34184230511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11503248143 - 26 = 11503248079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11503248193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5751624071 + 5751624072.
It is an arithmetic number, because the mean of its divisors is an integer number (5751624072).
Almost surely, 211503248143 is an apocalyptic number.
11503248143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11503248143 is an equidigital number, since it uses as much as digits as its factorization.
11503248143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 11503248143 its reverse (34184230511), we get a palindrome (45687478654).
The spelling of 11503248143 in words is "eleven billion, five hundred three million, two hundred forty-eight thousand, one hundred forty-three".
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