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115040315007 = 3241333092731
BaseRepresentation
bin110101100100011101…
…1111110011001111111
3101222221100122111201200
41223020323332121333
53341100310040012
6124503201110543
711211543354252
oct1531073763177
9358840574650
10115040315007
1144874293402
121a366928453
13ab04802817
1457d477b099
152ed48643dc
hex1ac8efe67f

115040315007 has 12 divisors (see below), whose sum is σ = 166209603144. Its totient is φ = 76674962160.

The previous prime is 115040314997. The next prime is 115040315029. The reversal of 115040315007 is 700513040511.

115040315007 is a `hidden beast` number, since 1 + 1 + 504 + 0 + 3 + 150 + 0 + 7 = 666.

It is not a de Polignac number, because 115040315007 - 26 = 115040314943 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115040315057) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1509169 + ... + 1583562.

It is an arithmetic number, because the mean of its divisors is an integer number (13850800262).

Almost surely, 2115040315007 is an apocalyptic number.

115040315007 is a deficient number, since it is larger than the sum of its proper divisors (51169288137).

115040315007 is a wasteful number, since it uses less digits than its factorization.

115040315007 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3096870 (or 3096867 counting only the distinct ones).

The product of its (nonzero) digits is 2100, while the sum is 27.

Adding to 115040315007 its reverse (700513040511), we get a palindrome (815553355518).

The spelling of 115040315007 in words is "one hundred fifteen billion, forty million, three hundred fifteen thousand, seven".

Divisors: 1 3 9 4133 12399 37197 3092731 9278193 27834579 12782257223 38346771669 115040315007