Base | Representation |
---|---|
bin | 11010001010000110010111… |
… | …110001101111011101011111 |
3 | 120002100000201120112222122112 |
4 | 122022012113301233131133 |
5 | 110034332031312004211 |
6 | 1044402045355504235 |
7 | 33142412603353544 |
oct | 3212062761573537 |
9 | 502300646488575 |
10 | 115043245422431 |
11 | 33724625962697 |
12 | 10aa019a15807b |
13 | 4c266ba8cb481 |
14 | 205a1a0d04bcb |
15 | d478137dc88b |
hex | 68a197c6f75f |
115043245422431 has 2 divisors, whose sum is σ = 115043245422432. Its totient is φ = 115043245422430.
The previous prime is 115043245422353. The next prime is 115043245422481. The reversal of 115043245422431 is 134224542340511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115043245422431 is a prime.
It is a super-2 number, since 2×1150432454224312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115043245422481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57521622711215 + 57521622711216.
It is an arithmetic number, because the mean of its divisors is an integer number (57521622711216).
Almost surely, 2115043245422431 is an apocalyptic number.
115043245422431 is a deficient number, since it is larger than the sum of its proper divisors (1).
115043245422431 is an equidigital number, since it uses as much as digits as its factorization.
115043245422431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 460800, while the sum is 41.
Adding to 115043245422431 its reverse (134224542340511), we get a palindrome (249267787762942).
The spelling of 115043245422431 in words is "one hundred fifteen trillion, forty-three billion, two hundred forty-five million, four hundred twenty-two thousand, four hundred thirty-one".
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