Base | Representation |
---|---|
bin | 10000101111011011100… |
… | …110011011001010111101 |
3 | 11001222111011212020212001 |
4 | 100233123212123022331 |
5 | 122322100240113401 |
6 | 2240301033342301 |
7 | 146054663223562 |
oct | 20573346331275 |
9 | 4058434766761 |
10 | 1150440551101 |
11 | 403998776666 |
12 | 166b68267991 |
13 | 84641bb6c0a |
14 | 3d978516869 |
15 | 1edd3d69601 |
hex | 10bdb99b2bd |
1150440551101 has 2 divisors, whose sum is σ = 1150440551102. Its totient is φ = 1150440551100.
The previous prime is 1150440551093. The next prime is 1150440551107. The reversal of 1150440551101 is 1011550440511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1149162560100 + 1277991001 = 1071990^2 + 35749^2 .
It is a cyclic number.
It is not a de Polignac number, because 1150440551101 - 23 = 1150440551093 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1150440551101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1150440551107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575220275550 + 575220275551.
It is an arithmetic number, because the mean of its divisors is an integer number (575220275551).
Almost surely, 21150440551101 is an apocalyptic number.
It is an amenable number.
1150440551101 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150440551101 is an equidigital number, since it uses as much as digits as its factorization.
1150440551101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2000, while the sum is 28.
Adding to 1150440551101 its reverse (1011550440511), we get a palindrome (2161990991612).
The spelling of 1150440551101 in words is "one trillion, one hundred fifty billion, four hundred forty million, five hundred fifty-one thousand, one hundred one".
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