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11504553113 is a prime number
BaseRepresentation
bin10101011011011100…
…11000110010011001
31002200202211211222202
422231232120302121
5142030131144423
65141330255545
7555044042114
oct125556306231
932622754882
1011504553113
114974025039
122290a275b5
131114614ca1
147b1ccd57b
15475006728
hex2adb98c99

11504553113 has 2 divisors, whose sum is σ = 11504553114. Its totient is φ = 11504553112.

The previous prime is 11504553107. The next prime is 11504553133. The reversal of 11504553113 is 31135540511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9092957449 + 2411595664 = 95357^2 + 49108^2 .

It is a cyclic number.

It is not a de Polignac number, because 11504553113 - 24 = 11504553097 is a prime.

It is not a weakly prime, because it can be changed into another prime (11504553133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5752276556 + 5752276557.

It is an arithmetic number, because the mean of its divisors is an integer number (5752276557).

Almost surely, 211504553113 is an apocalyptic number.

It is an amenable number.

11504553113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11504553113 is an equidigital number, since it uses as much as digits as its factorization.

11504553113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4500, while the sum is 29.

The spelling of 11504553113 in words is "eleven billion, five hundred four million, five hundred fifty-three thousand, one hundred thirteen".