Base | Representation |
---|---|
bin | 10000101111011101011… |
… | …111010000010100011011 |
3 | 11001222120101110111202020 |
4 | 100233131133100110123 |
5 | 122322131342213300 |
6 | 2240304124305523 |
7 | 146055526366464 |
oct | 20573537202433 |
9 | 4058511414666 |
10 | 1150472226075 |
11 | 403a04640527 |
12 | 166b769a22a3 |
13 | 846486273c3 |
14 | 3d97c7ddd6b |
15 | 1edd6a248a0 |
hex | 10bdd7d051b |
1150472226075 has 12 divisors (see below), whose sum is σ = 1902114080568. Its totient is φ = 613585187200.
The previous prime is 1150472226073. The next prime is 1150472226097. The reversal of 1150472226075 is 5706222740511.
It is not a de Polignac number, because 1150472226075 - 21 = 1150472226073 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1150472226073) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7669814766 + ... + 7669814915.
It is an arithmetic number, because the mean of its divisors is an integer number (158509506714).
Almost surely, 21150472226075 is an apocalyptic number.
1150472226075 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1150472226075 is a deficient number, since it is larger than the sum of its proper divisors (751641854493).
1150472226075 is a wasteful number, since it uses less digits than its factorization.
1150472226075 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15339629694 (or 15339629689 counting only the distinct ones).
The product of its (nonzero) digits is 235200, while the sum is 42.
Adding to 1150472226075 its reverse (5706222740511), we get a palindrome (6856694966586).
The spelling of 1150472226075 in words is "one trillion, one hundred fifty billion, four hundred seventy-two million, two hundred twenty-six thousand, seventy-five".
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