11505000655041 has 4 divisors (see below), whose sum is σ = 15340000873392. Its totient is φ = 7670000436692.

The previous prime is 11505000655039. The next prime is 11505000655103. The reversal of 11505000655041 is 14055600050511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11505000655041 - 2¹ = 11505000655039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11505000654993 and 11505000655011.

It is not an unprimeable number, because it can be changed into a prime (11505000655241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1917500109171 + ... + 1917500109176.

It is an arithmetic number, because the mean of its divisors is an integer number (3835000218348).

Almost surely, 2^{11505000655041} is an apocalyptic number.

It is an amenable number.

11505000655041 is a deficient number, since it is larger than the sum of its proper divisors (3835000218351).

11505000655041 is an equidigital number, since it uses as much as digits as its factorization.

11505000655041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3835000218350.

The product of its (nonzero) digits is 15000, while the sum is 33.

The spelling of 11505000655041 in words is "eleven trillion, five hundred five billion, six hundred fifty-five thousand, forty-one".