Base | Representation |
---|---|
bin | 11010001010001100110001… |
… | …001011011101010110101001 |
3 | 120002100200110021002011222002 |
4 | 122022030301023131112221 |
5 | 110034440113143422403 |
6 | 1044405143122140345 |
7 | 33143045035605344 |
oct | 3212146113352651 |
9 | 502320407064862 |
10 | 115050114045353 |
11 | 33727530034763 |
12 | 10aa15964b16b5 |
13 | 4c27243925ba6 |
14 | 205a65322345b |
15 | d47ab6805188 |
hex | 68a3312dd5a9 |
115050114045353 has 16 divisors (see below), whose sum is σ = 119940434864640. Its totient is φ = 110233540704000.
The previous prime is 115050114045337. The next prime is 115050114045437. The reversal of 115050114045353 is 353540411050511.
It is a cyclic number.
It is not a de Polignac number, because 115050114045353 - 24 = 115050114045337 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115050114045313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 122954801 + ... + 123886977.
It is an arithmetic number, because the mean of its divisors is an integer number (7496277179040).
Almost surely, 2115050114045353 is an apocalyptic number.
It is an amenable number.
115050114045353 is a deficient number, since it is larger than the sum of its proper divisors (4890320819287).
115050114045353 is a wasteful number, since it uses less digits than its factorization.
115050114045353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 971728.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 115050114045353 its reverse (353540411050511), we get a palindrome (468590525095864).
The spelling of 115050114045353 in words is "one hundred fifteen trillion, fifty billion, one hundred fourteen million, forty-five thousand, three hundred fifty-three".
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