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11505050113 is a prime number
BaseRepresentation
bin10101011011100000…
…10010001000000001
31002200210210002202011
422231300102020001
5142030243100423
65141345052521
7555051212104
oct125560221001
932623702664
1011505050113
114974334487
122291027141
13111475a27b
147b1dbc73b
154750a3b0d
hex2adc12201

11505050113 has 2 divisors, whose sum is σ = 11505050114. Its totient is φ = 11505050112.

The previous prime is 11505050111. The next prime is 11505050177. The reversal of 11505050113 is 31105050511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11472980544 + 32069569 = 107112^2 + 5663^2 .

It is a cyclic number.

It is not a de Polignac number, because 11505050113 - 21 = 11505050111 is a prime.

Together with 11505050111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11505050111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5752525056 + 5752525057.

It is an arithmetic number, because the mean of its divisors is an integer number (5752525057).

Almost surely, 211505050113 is an apocalyptic number.

It is an amenable number.

11505050113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11505050113 is an equidigital number, since it uses as much as digits as its factorization.

11505050113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 375, while the sum is 22.

The spelling of 11505050113 in words is "eleven billion, five hundred five million, fifty thousand, one hundred thirteen".