Base | Representation |
---|---|
bin | 110101100100110101… |
… | …0100000010100000001 |
3 | 101222222012121012120011 |
4 | 1223021222200110001 |
5 | 3341111420400023 |
6 | 124504314344521 |
7 | 11212052135431 |
oct | 1531152402401 |
9 | 358865535504 |
10 | 115052512513 |
11 | 44880164594 |
12 | 1a36aa2b141 |
13 | ab071b3693 |
14 | 57d62342c1 |
15 | 2ed597350d |
hex | 1ac9aa0501 |
115052512513 has 2 divisors, whose sum is σ = 115052512514. Its totient is φ = 115052512512.
The previous prime is 115052512511. The next prime is 115052512517. The reversal of 115052512513 is 315215250511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 88127640769 + 26924871744 = 296863^2 + 164088^2 .
It is a cyclic number.
It is not a de Polignac number, because 115052512513 - 21 = 115052512511 is a prime.
Together with 115052512511, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (115052512511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57526256256 + 57526256257.
It is an arithmetic number, because the mean of its divisors is an integer number (57526256257).
Almost surely, 2115052512513 is an apocalyptic number.
It is an amenable number.
115052512513 is a deficient number, since it is larger than the sum of its proper divisors (1).
115052512513 is an equidigital number, since it uses as much as digits as its factorization.
115052512513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 115052512513 in words is "one hundred fifteen billion, fifty-two million, five hundred twelve thousand, five hundred thirteen".
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