Base | Representation |
---|---|
bin | 11010001010001111100011… |
… | …110100101111010001100111 |
3 | 120002100222012010202222110021 |
4 | 122022033203310233101213 |
5 | 110040012232432223421 |
6 | 1044410400345540011 |
7 | 33143212231235053 |
oct | 3212174364572147 |
9 | 502328163688407 |
10 | 115053111211111 |
11 | 33728828939757 |
12 | 10aa20921a4607 |
13 | 4c27600857358 |
14 | 205a8592ccc63 |
15 | d47bde9d9341 |
hex | 68a3e3d2f467 |
115053111211111 has 2 divisors, whose sum is σ = 115053111211112. Its totient is φ = 115053111211110.
The previous prime is 115053111211067. The next prime is 115053111211117. The reversal of 115053111211111 is 111112111350511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115053111211111 - 223 = 115053102822503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115053111211117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57526555605555 + 57526555605556.
It is an arithmetic number, because the mean of its divisors is an integer number (57526555605556).
Almost surely, 2115053111211111 is an apocalyptic number.
115053111211111 is a deficient number, since it is larger than the sum of its proper divisors (1).
115053111211111 is an equidigital number, since it uses as much as digits as its factorization.
115053111211111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 150, while the sum is 25.
Adding to 115053111211111 its reverse (111112111350511), we get a palindrome (226165222561622).
The spelling of 115053111211111 in words is "one hundred fifteen trillion, fifty-three billion, one hundred eleven million, two hundred eleven thousand, one hundred eleven".
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