1150536445151 has 4 divisors (see below), whose sum is σ = 1175015944032. Its totient is φ = 1126056946272.

The previous prime is 1150536445141. The next prime is 1150536445199. The reversal of 1150536445151 is 1515446350511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1150536445151 - 2³⁰ = 1149462703327 is a prime.

It is a super-3 number, since 3×1150536445151³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1150536445099 and 1150536445108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150536445141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12239749370 + ... + 12239749463.

It is an arithmetic number, because the mean of its divisors is an integer number (293753986008).

Almost surely, 2^{1150536445151} is an apocalyptic number.

1150536445151 is a deficient number, since it is larger than the sum of its proper divisors (24479498881).

1150536445151 is an equidigital number, since it uses as much as digits as its factorization.

1150536445151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24479498880.

The product of its (nonzero) digits is 180000, while the sum is 41.

The spelling of 1150536445151 in words is "one trillion, one hundred fifty billion, five hundred thirty-six million, four hundred forty-five thousand, one hundred fifty-one".