Base | Representation |
---|---|
bin | 110101100100111010… |
… | …1000001011110100011 |
3 | 101222222101210021211201 |
4 | 1223021311001132203 |
5 | 3341113122113140 |
6 | 124504453422031 |
7 | 11212114441234 |
oct | 1531165013643 |
9 | 358871707751 |
10 | 115055269795 |
11 | 44881778134 |
12 | 1a36b93a917 |
13 | ab0793a6cb |
14 | 57d675108b |
15 | 2ed5d1a49a |
hex | 1ac9d417a3 |
115055269795 has 4 divisors (see below), whose sum is σ = 138066323760. Its totient is φ = 92044215832.
The previous prime is 115055269793. The next prime is 115055269837. The reversal of 115055269795 is 597962550511.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 115055269795 - 21 = 115055269793 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115055269793) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11505526975 + ... + 11505526984.
It is an arithmetic number, because the mean of its divisors is an integer number (34516580940).
Almost surely, 2115055269795 is an apocalyptic number.
115055269795 is a deficient number, since it is larger than the sum of its proper divisors (23011053965).
115055269795 is an equidigital number, since it uses as much as digits as its factorization.
115055269795 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23011053964.
The product of its (nonzero) digits is 4252500, while the sum is 55.
The spelling of 115055269795 in words is "one hundred fifteen billion, fifty-five million, two hundred sixty-nine thousand, seven hundred ninety-five".
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