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1150637992253 is a prime number
BaseRepresentation
bin10000101111100111010…
…111100110100100111101
311001222222221101022012022
4100233213113212210331
5122323001311223003
62240332405245525
7146062611363011
oct20574727464475
94058887338168
101150637992253
11403a8a171072
121670024038a5
1384673a865b9
143d996830541
151ede636a738
hex10be75e693d

1150637992253 has 2 divisors, whose sum is σ = 1150637992254. Its totient is φ = 1150637992252.

The previous prime is 1150637992249. The next prime is 1150637992267. The reversal of 1150637992253 is 3522997360511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 854992416964 + 295645575289 = 924658^2 + 543733^2 .

It is a cyclic number.

It is not a de Polignac number, because 1150637992253 - 22 = 1150637992249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1150637992195 and 1150637992204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1150637998253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575318996126 + 575318996127.

It is an arithmetic number, because the mean of its divisors is an integer number (575318996127).

Almost surely, 21150637992253 is an apocalyptic number.

It is an amenable number.

1150637992253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150637992253 is an equidigital number, since it uses as much as digits as its factorization.

1150637992253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3061800, while the sum is 53.

The spelling of 1150637992253 in words is "one trillion, one hundred fifty billion, six hundred thirty-seven million, nine hundred ninety-two thousand, two hundred fifty-three".