Base | Representation |
---|---|
bin | 1101101101111… |
… | …01010000111011 |
3 | 22000112011101021 |
4 | 12312331100323 |
5 | 213424220021 |
6 | 15230203311 |
7 | 2565036040 |
oct | 666752073 |
9 | 260464337 |
10 | 115070011 |
11 | 59a54891 |
12 | 32653537 |
13 | 1aabbc84 |
14 | 113d51c7 |
15 | a17ec41 |
hex | 6dbd43b |
115070011 has 4 divisors (see below), whose sum is σ = 131508592. Its totient is φ = 98631432.
The previous prime is 115069987. The next prime is 115070017. The reversal of 115070011 is 110070511.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110070511 = 1579 ⋅69709.
It is a cyclic number.
It is not a de Polignac number, because 115070011 - 25 = 115069979 is a prime.
It is a super-3 number, since 3×1150700113 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (115070017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8219280 + ... + 8219293.
It is an arithmetic number, because the mean of its divisors is an integer number (32877148).
Almost surely, 2115070011 is an apocalyptic number.
115070011 is a deficient number, since it is larger than the sum of its proper divisors (16438581).
115070011 is an equidigital number, since it uses as much as digits as its factorization.
115070011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16438580.
The product of its (nonzero) digits is 35, while the sum is 16.
The square root of 115070011 is about 10727.0690778050. The cubic root of 115070011 is about 486.3930770269.
The spelling of 115070011 in words is "one hundred fifteen million, seventy thousand, eleven".
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