Base | Representation |
---|---|
bin | 11010001010111101010100… |
… | …111010110101110111101111 |
3 | 120002112200000221020120020220 |
4 | 122022331110322311313233 |
5 | 110041313403314323110 |
6 | 1044445124542542423 |
7 | 33146602065012141 |
oct | 3212752472656757 |
9 | 502480027216226 |
10 | 115102253276655 |
11 | 337476562a0967 |
12 | 10aab707897a13 |
13 | 4c2c13293b448 |
14 | 205cd9bad2c91 |
15 | d49118db1370 |
hex | 68af54eb5def |
115102253276655 has 16 divisors (see below), whose sum is σ = 184184626295904. Its totient is φ = 61380861396480.
The previous prime is 115102253276611. The next prime is 115102253276657. The reversal of 115102253276655 is 556672352201511.
It is not a de Polignac number, because 115102253276655 - 219 = 115102252752367 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115102253276598 and 115102253276607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115102253276657) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 437802814 + ... + 438065643.
It is an arithmetic number, because the mean of its divisors is an integer number (11511539143494).
Almost surely, 2115102253276655 is an apocalyptic number.
115102253276655 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115102253276655 is a deficient number, since it is larger than the sum of its proper divisors (69082373019249).
115102253276655 is an equidigital number, since it uses as much as digits as its factorization.
115102253276655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 875877226.
The product of its (nonzero) digits is 3780000, while the sum is 51.
The spelling of 115102253276655 in words is "one hundred fifteen trillion, one hundred two billion, two hundred fifty-three million, two hundred seventy-six thousand, six hundred fifty-five".
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