Base | Representation |
---|---|
bin | 10000110000000011001… |
… | …010111011011110110011 |
3 | 11002001012110001220022101 |
4 | 100300003022323132303 |
5 | 122324430213311201 |
6 | 2240450550521231 |
7 | 146110304142550 |
oct | 20600312733663 |
9 | 4061173056271 |
10 | 1151104432051 |
11 | 4041a9496202 |
12 | 167112666217 |
13 | 847195bb092 |
14 | 3d9dc76ba27 |
15 | 1ee222a4d01 |
hex | 10c032bb7b3 |
1151104432051 has 8 divisors (see below), whose sum is σ = 1331397897984. Its totient is φ = 974773460040.
The previous prime is 1151104432013. The next prime is 1151104432069. The reversal of 1151104432051 is 1502344011511.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1151104432051 - 27 = 1151104431923 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1151104432351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 990622855 + ... + 990624016.
It is an arithmetic number, because the mean of its divisors is an integer number (166424737248).
Almost surely, 21151104432051 is an apocalyptic number.
1151104432051 is a deficient number, since it is larger than the sum of its proper divisors (180293465933).
1151104432051 is an equidigital number, since it uses as much as digits as its factorization.
1151104432051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1981246961.
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 1151104432051 its reverse (1502344011511), we get a palindrome (2653448443562).
The spelling of 1151104432051 in words is "one trillion, one hundred fifty-one billion, one hundred four million, four hundred thirty-two thousand, fifty-one".
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