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115112140413 = 338370713471
BaseRepresentation
bin110101100110100110…
…1111101111001111101
3102000010100210121122220
41223031031331321331
53341222201443123
6124514244355553
711213405022624
oct1531515757175
9360110717586
10115112140413
1144900890946
121a3869a5bb9
13ab1666016a
1458001166bb
152edad00ce3
hex1acd37de7d

115112140413 has 4 divisors (see below), whose sum is σ = 153482853888. Its totient is φ = 76741426940.

The previous prime is 115112140391. The next prime is 115112140417. The reversal of 115112140413 is 314041211511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115112140413 - 221 = 115110043261 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115112140417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19185356733 + ... + 19185356738.

It is an arithmetic number, because the mean of its divisors is an integer number (38370713472).

Almost surely, 2115112140413 is an apocalyptic number.

It is an amenable number.

115112140413 is a deficient number, since it is larger than the sum of its proper divisors (38370713475).

115112140413 is an equidigital number, since it uses as much as digits as its factorization.

115112140413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38370713474.

The product of its (nonzero) digits is 480, while the sum is 24.

Adding to 115112140413 its reverse (314041211511), we get a palindrome (429153351924).

The spelling of 115112140413 in words is "one hundred fifteen billion, one hundred twelve million, one hundred forty thousand, four hundred thirteen".

Divisors: 1 3 38370713471 115112140413