1151122444341 has 4 divisors (see below), whose sum is σ = 1534829925792. Its totient is φ = 767414962892.

The previous prime is 1151122444331. The next prime is 1151122444357. The reversal of 1151122444341 is 1434442211511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1151122444341 - 2⁵ = 1151122444309 is a prime.

It is a super-3 number, since 3×1151122444341³ (a number of 37 digits) contains 333 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1151122444331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191853740721 + ... + 191853740726.

It is an arithmetic number, because the mean of its divisors is an integer number (383707481448).

Almost surely, 2^{1151122444341} is an apocalyptic number.

It is an amenable number.

1151122444341 is a deficient number, since it is larger than the sum of its proper divisors (383707481451).

1151122444341 is an equidigital number, since it uses as much as digits as its factorization.

1151122444341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383707481450.

The product of its digits is 15360, while the sum is 33.

Adding to 1151122444341 its reverse (1434442211511), we get a palindrome (2585564655852).

It can be divided in two parts, 115112 and 2444341, that added together give a triangular number (2559453 = T₂₂₆₂).

The spelling of 1151122444341 in words is "one trillion, one hundred fifty-one billion, one hundred twenty-two million, four hundred forty-four thousand, three hundred forty-one".