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1151131330 = 25115113133
BaseRepresentation
bin100010010011100…
…1101111011000010
32222020001112022201
41010213031323002
54324142200310
6310120423414
740345312006
oct10447157302
92866045281
101151131330
11540869008
12281617b6a
13154643ccb
14acc4c706
156b0d5e3a
hex449cdec2

1151131330 has 8 divisors (see below), whose sum is σ = 2072036412. Its totient is φ = 460452528.

The previous prime is 1151131271. The next prime is 1151131343. The reversal of 1151131330 is 331311511.

It can be written as a sum of positive squares in 2 ways, for example, as 1062564409 + 88566921 = 32597^2 + 9411^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1151131298 and 1151131307.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57556557 + ... + 57556576.

Almost surely, 21151131330 is an apocalyptic number.

1151131330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1151131330 is a deficient number, since it is larger than the sum of its proper divisors (920905082).

1151131330 is a wasteful number, since it uses less digits than its factorization.

1151131330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 115113140.

The product of its (nonzero) digits is 135, while the sum is 19.

The square root of 1151131330 is about 33928.3263660323. The cubic root of 1151131330 is about 1048.0330007527.

Adding to 1151131330 its reverse (331311511), we get a palindrome (1482442841).

The spelling of 1151131330 in words is "one billion, one hundred fifty-one million, one hundred thirty-one thousand, three hundred thirty".

Divisors: 1 2 5 10 115113133 230226266 575565665 1151131330